(x^2+10x+20)/(x+5)

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Solution for (x^2+10x+20)/(x+5) equation: 


D( x )

x+5 = 0

x+5 = 0

x+5 = 0

x+5 = 0 // - 5

x = -5

x in (-oo:-5) U (-5:+oo)

(x^2+10*x+20)/(x+5) = 0

x^2+10*x+20 = 0

x^2+10*x+20 = 0

DELTA = 10^2-(1*4*20)

DELTA = 20

DELTA > 0

x = (20^(1/2)-10)/(1*2) or x = (-20^(1/2)-10)/(1*2)

x = (2*5^(1/2)-10)/2 or x = (-2*5^(1/2)-10)/2

(x-((-2*5^(1/2)-10)/2))*(x-((2*5^(1/2)-10)/2)) = 0

((x-((-2*5^(1/2)-10)/2))*(x-((2*5^(1/2)-10)/2)))/(x+5) = 0

( x-((-2*5^(1/2)-10)/2) )

x-((-2*5^(1/2)-10)/2) = 0 // + (-2*5^(1/2)-10)/2

x = (-2*5^(1/2)-10)/2

( x-((2*5^(1/2)-10)/2) )

x-((2*5^(1/2)-10)/2) = 0 // + (2*5^(1/2)-10)/2

x = (2*5^(1/2)-10)/2

x in { (-2*5^(1/2)-10)/2, (2*5^(1/2)-10)/2 }

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